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A television newscaster from a 24-hour news station wants to estimate the number of hours per day its viewers watch programming on this channel. The newscaster randomly selects 100 viewers and asks them how many hours per day they watch this station. The newscaster constructs an 85% confidence interval for the true mean number of hours viewers watch this station. Which of the following would decrease the margin of error?

A. Using a sample of size 50
B. Using a sample of size 200
C. Constructing a 90% confidence interval
D. Constructing a 95% confidence interval

Answer :

The correct option which would decrease the margin of error is Option B.

The margin of error is inversely proportional to the square root of the sample size. This means that increasing the sample size will decrease the margin of error.

Constructing a 90% confidence interval will increase the margin of error, and constructing a 95% confidence interval will increase the margin of error even more. This is because a higher confidence level requires a wider confidence interval.

Therefore, the correct option is using a sample size of 200.

Learn more on margin of error :https://brainly.com/question/15691460

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