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Answer :
Final answer:
The mass of ethanol that can be boiled with 762.4 KJ of heat energy is approximately 19.75 grams.
Explanation:
To calculate the mass of ethanol that can be boiled with a given amount of heat energy, we can use the equation:
mass = (heat energy)/(molar heat of vaporization)
First, we need to convert the given heat energy from kilojoules (KJ) to joules (J) by multiplying it by 1000:
762.4 KJ * 1000 = 762400 J
Next, we can substitute the values into the equation:
mass = 762400 J / 38.6 kJ/mol
Now, we need to convert the molar heat of vaporization from kilojoules per mole (kJ/mol) to joules per mole (J/mol) by multiplying it by 1000:
38.6 kJ/mol * 1000 = 38600 J/mol
Finally, we can calculate the mass of ethanol:
mass = 762400 J / 38600 J/mol
mass ≈ 19.75 grams
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