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Answer :
Final answer:
Using Charles's Law, the volume of a helium balloon will increase from 35.8 L to 42.1 L when the temperature is raised from 300 K to 353 K; the answer is (A) 42.1 L.
Explanation:
The question involves the concept of how temperature affects gas volume, which we can explain through Charles's Law. This law states that, for a given amount of gas at constant pressure, the volume of the gas is directly proportional to its temperature measured in Kelvin. To find the new volume when the temperature is raised from 300 K to 353 K, we use the formula:
V1/T1 = V2/T2
Substituting the known values:
35.8 L / 300 K = V2 / 353 K
Now, solving for V2:
V2 = (35.8 L × 353 K) / 300 K
V2 = 42.1 L
Therefore, when the helium balloon is heated from 300 K to 353 K, its volume will become 42.1 L. The correct answer is A. 42.1 L.
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