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A 215 kg object and a 515 kg object are separated by 0.500 m. Find the net gravitational force exerted by these objects on a 70.0 kg object placed midway between them.

Answer :

The net gravitational force on a 70.0 kg object placed midway between a 215 kg and a 515 kg object can be calculated using Newton's law of universal gravitation, by determining the gravitational forces exerted by each object on the 70.0 kg object and summing them up.

The question asks about the net gravitational force exerted by a 215 kg object and a 515 kg object on a 70.0 kg object placed midway between them, separated by a distance of 0.500 m.

To solve this problem, we can use Newton's law of universal gravitation, which states that the force of gravity between two masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. First, we calculate the gravitational force between the 70.0 kg object and the 215 kg object. Then, we calculate the force between the 70.0 kg object and the 515 kg object.

Since the 70.0 kg object is equidistant from both objects, the net gravitational force will be the sum of these two forces, as they are exerted in opposite directions. The formula for gravitational force is F = G * (m1*m2) / d^2, where G is the gravitational constant (6.674×10^-11 N(m/kg)^2), m1 and m2 are the masses of the two objects, and d is the distance between the centers of the two masses.

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