We appreciate your visit to 5 marks A box of mass 40 kg is pushed horizontally across the floor with a force of 185 N a Determine the weight of. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Sure, let's solve the problem step-by-step!
a) Determine the weight of the box:
To find the weight of the box, we use the formula:
[tex]\[ \text{Weight} = \text{mass} \times \text{gravity} \][/tex]
Given:
- Mass of the box = 40 kg
- Gravity = 9.8 m/s²
Plugging in these values:
[tex]\[ \text{Weight} = 40 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 392 \, \text{N} \][/tex]
So, the weight of the box is 392 N.
b) The size of the normal force:
On a horizontal surface, the normal force is equal to the weight of the object because there's no vertical acceleration.
Therefore, the normal force is:
[tex]\[ \text{Normal Force} = 392 \, \text{N} \][/tex]
c) The size of the frictional force:
The frictional force can be calculated using the coefficient of friction and the normal force. The formula is:
[tex]\[ \text{Frictional Force} = \text{coefficient of friction} \times \text{Normal Force} \][/tex]
Given:
- Coefficient of friction = 0.3
Plugging in these values:
[tex]\[ \text{Frictional Force} = 0.3 \times 392 \, \text{N} = 117.6 \, \text{N} \][/tex]
So, the frictional force is 117.6 N.
d) The resulting acceleration of the box:
To find the acceleration, we can use Newton's second law, which states:
[tex]\[ \text{Net Force} = \text{mass} \times \text{acceleration} \][/tex]
The net force is the difference between the applied force and the frictional force:
[tex]\[ \text{Net Force} = \text{Force applied} - \text{Frictional Force} \][/tex]
Given:
- Force applied = 185 N
Plugging in the values:
[tex]\[ \text{Net Force} = 185 \, \text{N} - 117.6 \, \text{N} = 67.4 \, \text{N} \][/tex]
Now, we calculate the acceleration:
[tex]\[ \text{Acceleration} = \frac{\text{Net Force}}{\text{mass}} \][/tex]
[tex]\[ \text{Acceleration} = \frac{67.4 \, \text{N}}{40 \, \text{kg}} = 1.685 \, \text{m/s}^2 \][/tex]
So, the resulting acceleration of the box is 1.685 m/s².
a) Determine the weight of the box:
To find the weight of the box, we use the formula:
[tex]\[ \text{Weight} = \text{mass} \times \text{gravity} \][/tex]
Given:
- Mass of the box = 40 kg
- Gravity = 9.8 m/s²
Plugging in these values:
[tex]\[ \text{Weight} = 40 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 392 \, \text{N} \][/tex]
So, the weight of the box is 392 N.
b) The size of the normal force:
On a horizontal surface, the normal force is equal to the weight of the object because there's no vertical acceleration.
Therefore, the normal force is:
[tex]\[ \text{Normal Force} = 392 \, \text{N} \][/tex]
c) The size of the frictional force:
The frictional force can be calculated using the coefficient of friction and the normal force. The formula is:
[tex]\[ \text{Frictional Force} = \text{coefficient of friction} \times \text{Normal Force} \][/tex]
Given:
- Coefficient of friction = 0.3
Plugging in these values:
[tex]\[ \text{Frictional Force} = 0.3 \times 392 \, \text{N} = 117.6 \, \text{N} \][/tex]
So, the frictional force is 117.6 N.
d) The resulting acceleration of the box:
To find the acceleration, we can use Newton's second law, which states:
[tex]\[ \text{Net Force} = \text{mass} \times \text{acceleration} \][/tex]
The net force is the difference between the applied force and the frictional force:
[tex]\[ \text{Net Force} = \text{Force applied} - \text{Frictional Force} \][/tex]
Given:
- Force applied = 185 N
Plugging in the values:
[tex]\[ \text{Net Force} = 185 \, \text{N} - 117.6 \, \text{N} = 67.4 \, \text{N} \][/tex]
Now, we calculate the acceleration:
[tex]\[ \text{Acceleration} = \frac{\text{Net Force}}{\text{mass}} \][/tex]
[tex]\[ \text{Acceleration} = \frac{67.4 \, \text{N}}{40 \, \text{kg}} = 1.685 \, \text{m/s}^2 \][/tex]
So, the resulting acceleration of the box is 1.685 m/s².
Thanks for taking the time to read 5 marks A box of mass 40 kg is pushed horizontally across the floor with a force of 185 N a Determine the weight of. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
