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Answer :
To express the equation of line L1, which is given in the standard form [tex]\(7x - 5y = -10\)[/tex], in the slope-intercept form [tex]\(y = mx + b\)[/tex], follow these steps:
1. Isolate the term with [tex]\(y\)[/tex]:
Start by moving the [tex]\(7x\)[/tex] term to the other side of the equation by subtracting [tex]\(7x\)[/tex] from both sides:
[tex]\[
7x - 5y = -10 \quad \Rightarrow \quad -5y = -7x - 10
\][/tex]
2. Solve for [tex]\(y\)[/tex]:
Next, eliminate the coefficient of [tex]\(y\)[/tex] by dividing every term in the equation by [tex]\(-5\)[/tex]:
[tex]\[
-5y = -7x - 10 \quad \Rightarrow \quad y = \frac{-7}{-5}x + \frac{-10}{-5}
\][/tex]
Simplify the fractions:
[tex]\[
y = \frac{7}{5}x + 2
\][/tex]
Now, the equation is in the slope-intercept form [tex]\(y = mx + b\)[/tex], where:
- The slope [tex]\(m\)[/tex] is [tex]\(\frac{7}{5}\)[/tex].
- The [tex]\(y\)[/tex]-intercept [tex]\(b\)[/tex] is [tex]\(2\)[/tex].
So the slope-intercept form of the equation is [tex]\(y = \frac{7}{5}x + 2\)[/tex].
1. Isolate the term with [tex]\(y\)[/tex]:
Start by moving the [tex]\(7x\)[/tex] term to the other side of the equation by subtracting [tex]\(7x\)[/tex] from both sides:
[tex]\[
7x - 5y = -10 \quad \Rightarrow \quad -5y = -7x - 10
\][/tex]
2. Solve for [tex]\(y\)[/tex]:
Next, eliminate the coefficient of [tex]\(y\)[/tex] by dividing every term in the equation by [tex]\(-5\)[/tex]:
[tex]\[
-5y = -7x - 10 \quad \Rightarrow \quad y = \frac{-7}{-5}x + \frac{-10}{-5}
\][/tex]
Simplify the fractions:
[tex]\[
y = \frac{7}{5}x + 2
\][/tex]
Now, the equation is in the slope-intercept form [tex]\(y = mx + b\)[/tex], where:
- The slope [tex]\(m\)[/tex] is [tex]\(\frac{7}{5}\)[/tex].
- The [tex]\(y\)[/tex]-intercept [tex]\(b\)[/tex] is [tex]\(2\)[/tex].
So the slope-intercept form of the equation is [tex]\(y = \frac{7}{5}x + 2\)[/tex].
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