High School

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The table below shows the heights of 6 pairs of brothers and sisters, labeled A through F. Heights are rounded to the nearest inch.

[tex]
\[
\begin{tabular}{|l|c|c|c|c|c|c|}
\hline
& \multicolumn{6}{|c|}{Pair} \\
\hline
\multicolumn{1}{|c|}{} & A & B & C & D & E & F \\
\hline
Brother's height (inches) & 68 & 70 & 68 & 71 & 69 & 71 \\
\hline
Sister's height (inches) & 64 & 66 & 65 & 71 & 66 & 67 \\
\hline
\end{tabular}
\]
[/tex]

The line of best fit for this data is [tex] y = 1.42105x - 32.2632 [/tex].

For the brother and sister whose heights are both 71 inches, what is the difference between the sister's actual height and the height predicted by the line of best fit?

[tex] \square [/tex]

Answer :

We start with the information that for this pair both the brother's and sister's actual heights are [tex]$71$[/tex] inches. The line of best fit is given by

[tex]$$
y = 1.42105x - 32.2632,
$$[/tex]

where [tex]$x$[/tex] is the brother's height and [tex]$y$[/tex] is the predicted sister's height.

1. Substitute the brother's height ([tex]$x = 71$[/tex]) into the equation to find the predicted sister's height:

[tex]$$
y = 1.42105(71) - 32.2632.
$$[/tex]

2. With the calculation, we find that the predicted sister's height is approximately:

[tex]$$
y \approx 68.63135\text{ inches}.
$$[/tex]

3. Next, we find the difference between the actual sister's height and the predicted sister's height. The actual sister's height is [tex]$71$[/tex] inches. Thus, the difference is:

[tex]$$
\text{Difference} = |71 - 68.63135| \approx 2.36865\text{ inches}.
$$[/tex]

Therefore, the sister's actual height is about [tex]$2.37$[/tex] inches different from what the line of best fit predicts.

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Rewritten by : Barada