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Answer :
The perimeter of the pentagon is irrelevant. The distance [tex]cc_2[/tex] is equal to the length of the hypotenuse of a triangle with legs of length 40 and 50 units. By the Pythagorean theorem,
[tex]{cc_2}^2 = 40^2 + 50^2 \implies cc_2 = \boxed{10\sqrt{41}}[/tex]
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