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Answer :
Final answer:
The molality of the ethanol in the solution is 18.17 mol/kg.
Explanation:
To calculate the molality of the ethanol in the solution, we need to determine the number of moles of ethanol and the mass of water in kilograms.
Given:
- Mass of ethanol = 100.5 g
- Molar mass of ethanol = 46.07 g/mol
- Mass of water = 120.0 g
- Molar mass of water = 18.02 g/mol
First, we calculate the number of moles of ethanol:
Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol
Number of moles of ethanol = 100.5 g / 46.07 g/mol
Number of moles of ethanol = 2.18 mol
Next, we convert the mass of water to kilograms:
Mass of water in kg = Mass of water / 1000
Mass of water in kg = 120.0 g / 1000
Mass of water in kg = 0.120 kg
Finally, we calculate the molality of the ethanol:
Molality = Number of moles of ethanol / Mass of water in kg
Molality = 2.18 mol / 0.120 kg
Molality = 18.17 mol/kg
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Final answer:
The molality of ethanol in the solution is calculated by converting the given mass of ethanol into moles, and the mass of water into kilograms. The molality is then found by dividing the moles of ethanol by the kilograms of water. The approximate molality of the solution is 18.17 mol/kg.
Explanation:
To calculate the molality (m) of the ethanol in the solution, we first convert the mass of ethanol to moles by dividing the given mass by its molar mass (MM).
So, moles of ethanol = 100.5 g ÷ 46.07 g/mol = 2.18 mol
The mass of water is converted from grams (g) to kilograms (Kg) by dividing by 1000, so mass of water = 120.0 g ÷ 1000 = 0.12 kg
Molality (m), is defined as the moles of solute (ethanol) divided by the mass of the solvent (water) in kilograms. Therefore, molality of ethanol in the solution = moles of ethanol ÷ mass of water in kg = 2.18 mol ÷ 0.12 kg = 18.17 m
So, the molality of the ethanol in the solution is approximately 18.17 mol/kg.
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