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A roller coaster with a potential energy of [tex]$235,200 \, \text{J}$[/tex] sits at the top of a 30 m high hill. What is the mass of the roller coaster?

(Formula: [tex]\text{PE} = mgh[/tex])

A. 800 kg
B. 7,840 kg
C. 8,000 kg
D. 78,400 kg

Answer :

We are given that the potential energy is

$$
PE = 235{,}200 \text{ J},
$$

the height is

$$
h = 30 \text{ m},
$$

and the acceleration due to gravity is

$$
g = 9.8 \text{ m/s}^2.
$$

The formula for potential energy is

$$
PE = mgh,
$$

where $m$ is the mass we need to find. We can solve for $m$ by rearranging the equation:

$$
m = \frac{PE}{gh}.
$$

Substitute the known values:

$$
m = \frac{235{,}200}{9.8 \times 30}.
$$

First, multiply $g$ and $h$:

$$
9.8 \times 30 = 294.
$$

Now, divide $PE$ by $294$:

$$
m = \frac{235{,}200}{294} = 800.
$$

Thus, the mass of the roller coaster is

$$
\boxed{800 \text{ kg}}.
$$

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Rewritten by : Barada