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Answer :
Final answer:
The percentage of American men aged 18-24 who are taller than 6 feet is calculated by converting the given height to inches, finding the z-score, and using it to find a percentile. Subtracting this percentile from 100 gives us the percentage of men taller than 6 feet, which is 5.5%
Explanation:
The question is asking about the proportion of American men in a specific age group that are taller than a certain height. To answer this, however, we need to convert the height 6 feet into inches because the given mean and standard deviation are in inches. Since 1 foot is 12 inches, 6 feet is 72 inches. Now, we find the z-score using the formula z = (X - μ) / σ, where X is the score (72 inches), μ is the mean (68 inches), and σ is the standard deviation (2.5 inches). This gives us a z-score of 1.6. From the z-score table, we see that a z-score of 1.6 corresponds to a percentile of 0.945 (or 94.5%). Therefore, 100 - 94.5 = 5.5% of men are taller than 6 feet, so the answer is c) 5.5.
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