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Answer :
The gas pressure after compressing the sample from 8.00 L to 2.00 L at constant temperature is 16.0 atm.
To find the gas pressure after compression, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume at a constant temperature.
Boyle's Law can be expressed as:
P1V1 = P2V2
where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.
Given:
Initial pressure (P1) = 4.00 atm
Initial volume (V1) = 8.00 L
Final volume (V2) = 2.00 L
Let's substitute these values into Boyle's Law:
P1V1 = P2V2
4.00 atm * 8.00 L = P2 * 2.00 L
32.00 atm * L = 2P2 * L
32.00 atm = 2P2
Dividing both sides by 2:
16.00 atm = P2
Therefore, the gas pressure after compression is 16.0 atm.
The gas pressure after compressing the sample from 8.00 L to 2.00 L at constant temperature is 16.0 atm.
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