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Answer :
Final answer:
To determine the volume of 1.5M NaOH needed to provide 0.75 mol of NaOH, utilize the molarity equation M1V1 = M2V2, resulting in a needed volume of 500 mL, which is option (c).
Explanation:
To solve the problem of how much volume of 1.5M NaOH is needed to provide 0.75 mol of NaOH, you would use the equation M1V1 = M2V2, where M1 is the molarity of the solution, V1 is the volume of the solution, M2 is the desired molarity, and V2 is the desired volume.
In this scenario, you are trying to find V1 (the volume of the 1.5M NaOH solution needed). We can rearrange the equation to solve for V1: V1 = M2V2 / M1.
M1 is given as 1.5M, and M2V2 is the amount of moles of NaOH needed, which is 0.75 mol. Substituting these into the equation provides: V1 = 0.75 mol / 1.5 mol/L = 0.5 L. Thus, the volume needed is 500 mL, which corresponds to option (c).
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Rewritten by : Barada
1.5M NaOH so we've 1.5 moles of NaOH in 1L of solution
1L = 1000 ml
1.5 moles of NaOH ------------in------------- 1000 ml
0.75 moles of NaOH ----------in---------------x ml
x = 500 ml
answer: C
1L = 1000 ml
1.5 moles of NaOH ------------in------------- 1000 ml
0.75 moles of NaOH ----------in---------------x ml
x = 500 ml
answer: C