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Answer :
To solve the equation [tex]\(\frac{1}{2}(x-14)+11=\frac{1}{2}x-(x-4)\)[/tex], let's go through the steps that Karissa followed:
1. Begin with the original equation:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x-4)
\][/tex]
2. Distribute the [tex]\(\frac{1}{2}\)[/tex] on the left side:
[tex]\[
\frac{1}{2}x - 7 + 11 = \frac{1}{2}x - (x-4)
\][/tex]
3. Simplify the left side by combining like terms ([tex]\(-7 + 11\)[/tex]):
[tex]\[
\frac{1}{2}x + 4 = \frac{1}{2}x - (x-4)
\][/tex]
4. Distribute the negative sign on the right side:
[tex]\[
\frac{1}{2}x + 4 = \frac{1}{2}x - x + 4
\][/tex]
5. Simplify the right side by combining like terms:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
6. Subtract 4 from both sides to isolate the x terms:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
7. Add [tex]\(\frac{1}{2}x\)[/tex] to both sides to combine all x terms:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
8. Combine the x terms:
[tex]\[
x = 0
\][/tex]
So, the value of [tex]\(x\)[/tex] is [tex]\(0\)[/tex].
1. Begin with the original equation:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x-4)
\][/tex]
2. Distribute the [tex]\(\frac{1}{2}\)[/tex] on the left side:
[tex]\[
\frac{1}{2}x - 7 + 11 = \frac{1}{2}x - (x-4)
\][/tex]
3. Simplify the left side by combining like terms ([tex]\(-7 + 11\)[/tex]):
[tex]\[
\frac{1}{2}x + 4 = \frac{1}{2}x - (x-4)
\][/tex]
4. Distribute the negative sign on the right side:
[tex]\[
\frac{1}{2}x + 4 = \frac{1}{2}x - x + 4
\][/tex]
5. Simplify the right side by combining like terms:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
6. Subtract 4 from both sides to isolate the x terms:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
7. Add [tex]\(\frac{1}{2}x\)[/tex] to both sides to combine all x terms:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
8. Combine the x terms:
[tex]\[
x = 0
\][/tex]
So, the value of [tex]\(x\)[/tex] is [tex]\(0\)[/tex].
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