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A 7.00 kg bowling ball is held 2.00 m above the ground. Using [tex]g=9.80 \, \text{m/s}^2[/tex], how much energy does the ball have due to its position?

A. 68.6 J
B. 137 J
C. 274 J
D. 960 J

Answer :

To find out how much energy the bowling ball has due to its position, we need to calculate its gravitational potential energy (PE). Gravitational potential energy is given by the formula:

[tex]\[ \text{PE} = m \times g \times h \][/tex]

where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.80 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).

Let's plug in the values:

1. The mass of the bowling ball [tex]\( m = 7.00 \, \text{kg} \)[/tex].
2. The gravitational acceleration [tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex].
3. The height above the ground [tex]\( h = 2.00 \, \text{m} \)[/tex].

Now, substitute these values into the formula:

[tex]\[ \text{PE} = 7.00 \, \text{kg} \times 9.80 \, \text{m/s}^2 \times 2.00 \, \text{m} \][/tex]

Calculate the potential energy:

[tex]\[ \text{PE} = 137 \, \text{J} \][/tex]

Therefore, the bowling ball has 137 Joules of potential energy due to its position.

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