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Answer :
To find out how much energy the bowling ball has due to its position, we need to calculate its gravitational potential energy (PE). Gravitational potential energy is given by the formula:
[tex]\[ \text{PE} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.80 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's plug in the values:
1. The mass of the bowling ball [tex]\( m = 7.00 \, \text{kg} \)[/tex].
2. The gravitational acceleration [tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex].
3. The height above the ground [tex]\( h = 2.00 \, \text{m} \)[/tex].
Now, substitute these values into the formula:
[tex]\[ \text{PE} = 7.00 \, \text{kg} \times 9.80 \, \text{m/s}^2 \times 2.00 \, \text{m} \][/tex]
Calculate the potential energy:
[tex]\[ \text{PE} = 137 \, \text{J} \][/tex]
Therefore, the bowling ball has 137 Joules of potential energy due to its position.
[tex]\[ \text{PE} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.80 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's plug in the values:
1. The mass of the bowling ball [tex]\( m = 7.00 \, \text{kg} \)[/tex].
2. The gravitational acceleration [tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex].
3. The height above the ground [tex]\( h = 2.00 \, \text{m} \)[/tex].
Now, substitute these values into the formula:
[tex]\[ \text{PE} = 7.00 \, \text{kg} \times 9.80 \, \text{m/s}^2 \times 2.00 \, \text{m} \][/tex]
Calculate the potential energy:
[tex]\[ \text{PE} = 137 \, \text{J} \][/tex]
Therefore, the bowling ball has 137 Joules of potential energy due to its position.
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