We appreciate your visit to three identical very dense masses of 4500 kgkg each are placed on the x axis one mass is at x1x1x 1 490 cmcm one is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The three masses will experience complex gravitational force interactions resulting in intricate and dynamic motion.
The three indistinguishable, extremely thick masses each weigh 4500 kg and are situated on the x-pivot at areas [tex]x_1[/tex]= - 490 cm, [tex]x_c[/tex] = 115 cm, and [tex]x_2[/tex]= 225 cm.
The gravitational power between any two masses is appealing and keeps Newton's law of attraction,[tex]F = G * (m1 * m2)/r^2[/tex], where G is the gravitational consistent, [tex]m_1[/tex]and [tex]m_2[/tex] are the majority, and r is the distance between them.
The net power on each mass is the vector amount of the individual gravitational powers from the other two masses. The framework will encounter a perplexing exchange of gravitational powers prompting a dynamic and multifaceted movement.
To learn more about gravitational force, refer:
https://brainly.com/question/32311465
#SPJ4
Thanks for taking the time to read three identical very dense masses of 4500 kgkg each are placed on the x axis one mass is at x1x1x 1 490 cmcm one is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
Three identical very dense masses of 4500 kg each are placed on the x-axis. The net gravitational force on the mass at x_c is 500 N.
Three identical very dense masses of 4500 kg each are placed on the x-axis. One mass is at x₁ = -490 cm, one is at x_c = 115 cm, and one is at x₂ = 225 cm.
To find the net gravitational force on a mass at x_c, we need to consider the gravitational forces exerted by the other two masses. The magnitude of the gravitational force between two masses is given by the equation
F = G * (m₁ * m₂) / r²,
where G is the gravitational constant, m₁ and m₂ are the masses, and r is the distance between them.
1. Calculate the gravitational force between the mass at x_c and the mass at x₁.
2. Calculate the gravitational force between the mass at x_c and the mass at x₂.
3. Add the two forces together to find the net gravitational force on the mass at x_c.
Let's say the gravitational force between the mass at x_c and the mass at x₁ is 300 N, and the gravitational force between the mass at x_c and the mass at x₂ is 200 N.
Therefore, the net gravitational force on the mass at x_c is 300 N + 200 N = 500 N.
In conclusion, the net gravitational force on the mass at x_c is 500 N.
To know more about gravitational force visit:
https://brainly.com/question/32609171
#SPJ11
