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Suppose many capacitors, each with [tex]C = 90 \, \mu F[/tex], are connected in parallel across a battery with a potential difference of [tex]V = 160 \, V[/tex]. How many capacitors are needed to store [tex]95.6 \, J[/tex] of energy?

Answer :

Final answer:

To calculate the number of capacitors needed to store a given amount of energy. Approximately 82.64 capacitors are needed to store 95 6j of energy.

Explanation:

To calculate the number of capacitors needed to store a given amount of energy, we can use the formula:

N = E / (1/2 * C * V^2)

Where N is the number of capacitors needed, E is the energy to be stored, C is the capacitance of each capacitor, and V is the potential difference across the capacitors.

In this case, the given values are:

Substituting these values into the formula:

N = 95 6j / (1/2 * 90 MF * (160 V)^2)

Simplifying the expression:

N = 95 6j / (1/2 * 90 * 10^-6 * 25600)

N = 95 6j / (0.000045 * 25600)

N = 95 6j / 1.152

N ≈ 82.64

Therefore, approximately 82.64 capacitors are needed to store 95 6j of energy.

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Rewritten by : Barada

Final answer:

Approximately 82.64 capacitors are needed to store 95 6j of energy.

Explanation:

To calculate the number of capacitors needed to store a given amount of energy, we can use the formula:

N = E / (1/2 * C * V^2)

Where N is the number of capacitors needed, E is the energy to be stored, C is the capacitance of each capacitor, and V is the potential difference across the capacitors.

In this case, the given values are:

Substituting these values into the formula:

N = 95 6j / (1/2 * 90 MF * (160 V)^2)

Simplifying the expression:

N = 95 6j / (1/2 * 90 * 10^-6 * 25600)

N = 95 6j / (0.000045 * 25600)

N = 95 6j / 1.152

N ≈ 82.64

Therefore, approximately 82.64 capacitors are needed to store 95 6j of energy.

Learn more about calculating the number of capacitors needed to store a given amount of energy here:

https://brainly.com/question/34023308

#SPJ14