High School

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At 100°C, the [tex]K_w[/tex] of water is [tex]5.6 \times 10^{-13}[/tex]. What is the pOH of a solution that has a pH of 6.25 at 100°C?

A) 6.00
B) 6.25
C) 7.00
D) 7.75
E) 8.00

Answer :

Final answer:

To find the pOH of a solution at 100°C with a pH of 6.25, we calculate the pKw from the given Kw and use the relationship pH + pOH = pKw. The pOH is found to be 7.75.

Explanation:

The student asked what the pOH of a solution is if it has a pH of 6.25 at 100°C and given that the Kw of water at this temperature is 5.6 x 10⁻¹³. To find the pOH, we first need to calculate the pKw, which is the negative base-10 logarithm of Kw. Using the given Kw value, pKw = -log(5.6 x 10⁻¹³). Once we have the pKw, we can use the relationship pH + pOH = pKw to find the pOH. Given the pH of 6.25, we can rearrange to pOH = pKw - pH. After computing the values, we find that the pOH of the solution at 100°C is 7.75.

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