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Answer :
To calculate the vapor composition of a solution, we can use Raoult's law, which states that the vapor pressure of a component in an ideal solution is directly proportional to its mole fraction in the liquid phase.
Let's assume that the mole fraction of acetone in the liquid phase is x_acetone and the mole fraction of cyclohexane is x_cyclohexane. According to Raoult's law, the partial pressure of acetone in the vapor phase, p_acetone, is given by p_acetone = p°acetone * x_acetone, where p°acetone is the vapor pressure of pure acetone.
Similarly, the partial pressure of cyclohexane in the vapor phase, p_cyclohexane, is given by p_cyclohexane = p°cyclohexane * x_cyclohexane, where p°cyclohexane is the vapor pressure of pure cyclohexane.
Since the total pressure above the solution is the sum of the partial pressures, we have: p_total = p_acetone + p_cyclohexane.
Now, let's solve the equations using the given values:
p°acetone = 229.5 torr
p°cyclohexane = 97.6 torr
We can rearrange the equations to find x_acetone and x_cyclohexane:
x_acetone = p_acetone / p°acetone
x_cyclohexane = p_cyclohexane / p°cyclohexane
Substituting the equations, we get:
x_acetone = (p°acetone * x_acetone) / p°acetone
x_cyclohexane = (p°cyclohexane * x_cyclohexane) / p°cyclohexane
Simplifying, we find:
x_acetone = x_acetone
x_cyclohexane = x_cyclohexane
Therefore, the mole fractions of acetone and cyclohexane in the vapor above the solution are the same as their mole fractionsin the liquid phase.
Learn more about vapor composition here : brainly.com/question/8598915
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