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Select the correct answer.

Paul is gathering data about moss growth in a local forest. He measured an area of 11 square centimeters on one particular tree and will come back in 6 months to measure the growth of the moss. If the area covered by moss multiplies by one and a half times each month, approximately how much area will the moss cover when Paul returns?

A. [tex]99.1 \, \text{cm}^2[/tex]

B. [tex]16.5 \, \text{cm}^2[/tex]

C. [tex]125.3 \, \text{cm}^2[/tex]

D. [tex]14.7 \, \text{cm}^2[/tex]

Answer :

We start by noting that the moss grows by multiplying its area by [tex]$1.5$[/tex] each month. The area after [tex]$n$[/tex] months can be calculated using the formula:

[tex]$$
\text{Final Area} = (\text{Initial Area}) \times (1.5)^n.
$$[/tex]

Here, the initial area is [tex]$11\, \text{cm}^2$[/tex] and the number of months is [tex]$6$[/tex]. Thus,

[tex]$$
\text{Final Area} = 11 \times (1.5)^6.
$$[/tex]

Next, we calculate [tex]$(1.5)^6$[/tex], which equals approximately [tex]$11.390625$[/tex]. Then, we multiply this factor by the initial area:

[tex]$$
\text{Final Area} \approx 11 \times 11.390625 \approx 125.296875\, \text{cm}^2.
$$[/tex]

Rounded to one decimal place, the area is approximately [tex]$125.3\, \text{cm}^2$[/tex].

Therefore, the correct answer is:

[tex]$$
\boxed{125.3\, \text{cm}^2}
$$[/tex]

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