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Answer :
We start by noting that the moss grows by multiplying its area by [tex]$1.5$[/tex] each month. The area after [tex]$n$[/tex] months can be calculated using the formula:
[tex]$$
\text{Final Area} = (\text{Initial Area}) \times (1.5)^n.
$$[/tex]
Here, the initial area is [tex]$11\, \text{cm}^2$[/tex] and the number of months is [tex]$6$[/tex]. Thus,
[tex]$$
\text{Final Area} = 11 \times (1.5)^6.
$$[/tex]
Next, we calculate [tex]$(1.5)^6$[/tex], which equals approximately [tex]$11.390625$[/tex]. Then, we multiply this factor by the initial area:
[tex]$$
\text{Final Area} \approx 11 \times 11.390625 \approx 125.296875\, \text{cm}^2.
$$[/tex]
Rounded to one decimal place, the area is approximately [tex]$125.3\, \text{cm}^2$[/tex].
Therefore, the correct answer is:
[tex]$$
\boxed{125.3\, \text{cm}^2}
$$[/tex]
[tex]$$
\text{Final Area} = (\text{Initial Area}) \times (1.5)^n.
$$[/tex]
Here, the initial area is [tex]$11\, \text{cm}^2$[/tex] and the number of months is [tex]$6$[/tex]. Thus,
[tex]$$
\text{Final Area} = 11 \times (1.5)^6.
$$[/tex]
Next, we calculate [tex]$(1.5)^6$[/tex], which equals approximately [tex]$11.390625$[/tex]. Then, we multiply this factor by the initial area:
[tex]$$
\text{Final Area} \approx 11 \times 11.390625 \approx 125.296875\, \text{cm}^2.
$$[/tex]
Rounded to one decimal place, the area is approximately [tex]$125.3\, \text{cm}^2$[/tex].
Therefore, the correct answer is:
[tex]$$
\boxed{125.3\, \text{cm}^2}
$$[/tex]
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