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Answer :
Therefore, the initial kinetic energy of the ball is approximately 10,587 J.
The initial kinetic energy of a 7.0 kg ball launched at 54 m/s at an angle of 67 degrees can be calculated as follows:
Step 1: Find the horizontal and vertical components of the velocity:
vx = v cos θ
vx = 54 cos 67°
vx = 21.9 m/s
vy = v sin θ
vy = 54 sin 67°
vy = 50.6 m/s
Step 2: Find the magnitude of the velocity:
|v| = √(vx² + vy²)
|v|= √(21.9² + 50.6²)
|v| = 55.4 m/s
Step 3: Calculate the initial kinetic energy of the ball:
KE = (1/2)mv²
KE = (1/2)(7.0 kg)(55.4 m/s)²
KE ≈ 10,587 J
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