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Answer :
The concentration of Ag+ ions in a saturated solution of Ag3PO4 at 25 degrees Celsius is 4.65 x 10−5 M, which is calculated by multiplying the solubility of Ag3PO4 (1.55 x 10−5 mol/L) by 3. Therefore, the correct answer is c. 4.65 x 10−5 M.
The student has asked a question about the concentration of Ag+ ions in a saturated solution of silver phosphate (Ag3PO4) at 25 degrees Celsius.
The solubility of Ag3PO4 at 25 degree C is 1.55 x 10−5 mol/L. When Ag3PO4 dissolves, it dissociates into three Ag+ ions and one PO43− ion. Hence, for every mole of Ag3PO4 dissolved, 3 moles of Ag+ ions are produced. This means that the concentration of Ag+ ions is 3 times the molar solubility of Ag3PO4.
Thus, the concentration of Ag+ in a saturated solution can be calculated as:
Concentration of Ag+ = 3 x (1.55 x 10−5 mol/L)
Concentration of Ag+ = 4.65 x 10−5 M
Therefore, the correct answer is c. 4.65 x 10−5 M.
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