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Answer :
Therefore, the approximate gravitational force on the International Space Station due to Earth's gravity when it orbited at an altitude of 400,000 m is approximately 2.44 × 10^6 Newtons.
To calculate the approximate gravitational force on the International Space Station (ISS) due to Earth's gravity, we can use the formula for gravitational force:
F = (G * m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2/kg^2), m1 and m2 are the masses of the two objects (in this case, the mass of the ISS and the mass of the Earth), and r is the distance between the centers of the two objects.
Given:
Mass of the ISS (m1) = 235,565 kg
Mass of the Earth (m2) = 5.972 × 10^24 kg
Distance between the ISS and the Earth's center (r) = 400,000 m
Plugging these values into the formula, we have:
F = (G * m1 * m2) / r^2
= (6.67430 × 10^-11 N m^2/kg^2) * (235,565 kg) * (5.972 × 10^24 kg) / (400,000 m)^2
Calculating this expression gives us the approximate gravitational force on the ISS due to Earth's gravity.
F ≈ 2.44 × 10^6 N
Therefore, the approximate gravitational force on the International Space Station due to Earth's gravity when it orbited at an altitude of 400,000 m is approximately 2.44 × 10^6 Newtons.
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