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Answer :
We start with the exponential equation
[tex]$$
2^x = 128.
$$[/tex]
Recall the definition of a logarithm: if
[tex]$$
a^c = b,
$$[/tex]
then it can be rewritten in logarithmic form as
[tex]$$
\log_a(b) = c.
$$[/tex]
In our problem, we have:
- Base: [tex]$a = 2$[/tex]
- Exponent: [tex]$c = x$[/tex]
- Result: [tex]$b = 128$[/tex]
Using the definition, we rewrite the exponential equation as:
[tex]$$
\log_{2}(128) = x.
$$[/tex]
Thus, the logarithmic form of the equation is [tex]$\boxed{\log_{2}(128) = x}$[/tex].
Moreover, if we calculate the value, we find:
[tex]$$
x = \log_2(128) = 7.
$$[/tex]
So the final answer is [tex]$\log_{2}(128) = x$[/tex], with [tex]$x = 7$[/tex].
[tex]$$
2^x = 128.
$$[/tex]
Recall the definition of a logarithm: if
[tex]$$
a^c = b,
$$[/tex]
then it can be rewritten in logarithmic form as
[tex]$$
\log_a(b) = c.
$$[/tex]
In our problem, we have:
- Base: [tex]$a = 2$[/tex]
- Exponent: [tex]$c = x$[/tex]
- Result: [tex]$b = 128$[/tex]
Using the definition, we rewrite the exponential equation as:
[tex]$$
\log_{2}(128) = x.
$$[/tex]
Thus, the logarithmic form of the equation is [tex]$\boxed{\log_{2}(128) = x}$[/tex].
Moreover, if we calculate the value, we find:
[tex]$$
x = \log_2(128) = 7.
$$[/tex]
So the final answer is [tex]$\log_{2}(128) = x$[/tex], with [tex]$x = 7$[/tex].
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