Answer :

The equation 2^x = 128 as a logarithmic equation is log₂(128) = x

How to rewrite the equation as a logarithmic equation?

The equation is given as:

2^x = 128

Take the logarithm of both sides

log(2^x) = log(128)

Rewrite as:

x * log(2) = log(128)

Divide both sides of the equation by log(2)

x = log(128)/log(2)

Apply the change of base rule

x = log₂(128)

Hence, the equation 2^x = 128 as a logarithmic equation is log₂(128) = x

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Rewritten by : Barada

The equation 2ˣ = 128, when rewritten as a logarithmic equation, becomes log₂(128) = X. The logarithm asks for the power to which the base (in this case, 2) must be raised to achieve the number 128.

To convert the equation 2ˣ = 128 to a logarithmic form, we need to understand what a logarithm represents. A logarithm with a base b of a given number x is the power to which b must be raised to produce x.

When 2 is raised to the power of x to equal 128, we are looking for the exponent x such that 2x = 128, which is indeed a logarithmic relationship. In this case, the base b is 2 and the number x is 128.

Therefore, the logarithmic form of the equation is log₂128 = x.

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