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Answer :
The steel rod weighs about 4,616 lb. Calculated by finding its volume and multiplying it by the weight per cubic foot.
The correct answer is c) 4,616 lb.
Find the volume of the steel rod.
Given that the rod is 12 ft. long and has a diameter of 1 foot, we can calculate its volume using the formula for the volume of a cylinder:
Volume = π × (radius)^2 × height
The radius (r) is half of the diameter, so r = 1/2 = 0.5 ft.
Plugging in the values, we get:
Volume = π × (0.5)^2 × 12
Volume ≈ 3.14 × 0.25 × 12
Volume ≈ 9.42 cubic feet
Calculate the weight of the steel rod.
Given that a cubic foot of steel weighs 490 lb., we can find the weight of the rod by multiplying its volume by the weight per cubic foot:
Weight = Volume × Weight per cubic foot
Weight ≈ 9.42 × 490
Weight ≈ 4615.8 lb
Since we need to round to the nearest pound, the weight of the rod is approximately 4,616 lb., which corresponds to option c).
The correct answer is c) 4,616 lb.
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