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A gas has a volume of 6.00 liters at a temperature of 27ºC and a pressure of 1.00 atm. What is the volume of the gas, in liters, at a temperature of 327ºC and a pressure of 3.00 atm?

Answer :

Answer:

4.00 liters

Explanation:

V1 = 6.00 liters, T1 = 27 C = 27 + 273 K = 300 K, P1 = 1.00 atm

V2 = ?, T2 = 327 C = 327 + 273 K = 600 K, P2 = 3.00 atm

Use P1*V1/T1 = P2*V2/T2

V2 = V1 * (P1/P2) * (T2/T1) = 6*(1/3)*(600/300) = 4.00 liters

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