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Answer :
Final answer:
The magnitude of the car's acceleration while braking is approximately -50.0 m/s^2.
Explanation:
To find the magnitude of the car's acceleration while braking, we can use the kinematic equation:
Final velocity squared = Initial velocity squared + 2 * acceleration * distance
We know the initial velocity is 50.0 km/h and the final velocity is 0 (since the car stops), and the distance is 35 m. Rearranging the equation, we can solve for acceleration:
acceleration = (Final velocity squared - Initial velocity squared) / (2 * distance)
Plugging in the values, we get:
acceleration = (0^2 - 50.0^2) / (2 * 35) = -50.0 m/s^2
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Answer:
Explanation:
The equation for acceleration is
[tex]a=\frac{v_f-v_0}{t}[/tex] where vf is final velocity, v0 is initial velocity and t is time in seconds. But we have a problem here because the initial velocity is given in km/hr while the distance is given in meters. We are going to change 50.0 km/hr to m/sec:
[tex]50\frac{km}{y\hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}[/tex] which gives us an initial velocity of
v = 13.9 m/s
But that still doesn't give us anything for the time, which is the denominator of the acceleration equation. We have to find it. Since this is one-dimensional travel, use d = rt to find the time it took for the car to travel 35 meters at a rate of 13.9 m/s:
35 = 13.9t and
t = 2.5 seconds. Now we can use that in the acceleration equation:
[tex]a=\frac{0-13.9}{2.5}[/tex] so
a = -5.6 m/s/s The negative sign tells us that the car is slowing down, as we would expect it to be when it is traveling at a certain rate and eventually stops.
