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Answer :
The x-distance from where the projectile was launched to where it lands is approximately 137.9 m, and the y-distance is approximately 71.6 m.
To determine the x and y distances, we can use the equations of motion for projectile motion. The horizontal and vertical components of motion are independent of each other.
The horizontal distance (x) traveled by the projectile can be found using the formula:
x = v0 * t * cos(theta)
where v0 is the initial speed, t is the time of flight, and theta is the launch angle
Substituting the given values, we have:
x = 60 * 3 * cos(40°) ≈ 137.9 m
The vertical distance (y) can be calculated using the formula:
y = v0 * t * sin(theta) - (1/2) * g * [tex]t^2[/tex]
where g is the acceleration due to gravity.
Substituting the given values, we have:
y = 60 * 3 * sin(40°) - (1/2) * 9.8 * ([tex]3^2[/tex]) ≈ 71.6 m
Therefore, the x-distance from where the projectile was launched to where it lands is approximately 137.9 m, and the y-distance is approximately 71.6 m.
Learn more about projectile motion here:
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