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Answer :
Final answer:
The intensity of a 120-W lightbulb observed from 2 m away is 2.4 W/m². According to the Inverse Square Law for Light, doubling the distance to 4 m will make the intensity one-fourth of the original, resulting in an intensity of 0.6 W/m².
Explanation:
To answer the student's question, we'll use the Inverse Square Law for Light. This law states that the intensity (brightness) of light coming from a point source (like a lightbulb) is inversely proportional to the square of the distance from the source. So, if the distance doubles, the intensity is reduced by a factor of 4 (given by 2², where 2 is the multiple by which the distance is increased).
For the given 120-W lightbulb, the intensity observed at 2 m is 2.4 W/m². If the distance is doubled to 4 m, the new intensity will be (1/2)² = 1/4 of the original intensity. Mathematically, it's calculated as:
Original intensity / (Distance factor)² = New intensity
2.4 W/m² / 4 = 0.6 W/m²
This means that at 4 m away, the lightbulb would have an intensity of 0.6 W/m².
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