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Answer :
To solve triangle ABC with the given information, we have the following details:
- Angle B = 35° 00'
- Side a = 38.5
- Side b = 30.9
We need to find the missing parts of the triangle, namely angle A, angle C, and side c.
Step-by-step Solution:
Find Angle A using the Law of Sines:
We can use the Law of Sines, which states:
[tex]\frac{a}{\sin A} = \frac{b}{\sin B}[/tex]Plug in the known values:
[tex]\frac{38.5}{\sin A} = \frac{30.9}{\sin 35°}[/tex]First, calculate [tex]\sin 35°[/tex]:
[tex]\sin 35° \approx 0.5736[/tex]Substitute [tex]\sin 35°[/tex] into the equation:
[tex]\frac{38.5}{\sin A} = \frac{30.9}{0.5736}[/tex][tex]\frac{38.5}{\sin A} = 53.87[/tex]
Solve for [tex]\sin A[/tex]:
[tex]\sin A = \frac{38.5}{53.87}[/tex][tex]\sin A \approx 0.7148[/tex]
Find angle A:
[tex]A \approx \sin^{-1}(0.7148)[/tex][tex]A \approx 45.60°[/tex]
Find Angle C:
Since the sum of angles in a triangle is 180°, we can find angle C:
[tex]C = 180° - B - A[/tex][tex]C = 180° - 35° - 45.60°[/tex]
[tex]C \approx 99.40°[/tex]
Find Side c using the Law of Sines:
Use the Law of Sines again:
[tex]\frac{c}{\sin C} = \frac{a}{\sin A}[/tex]Plug in the known values:
[tex]\frac{c}{\sin 99.40°} = \frac{38.5}{\sin 45.60°}[/tex]Calculate [tex]\sin 99.40°[/tex] and [tex]\sin 45.60°[/tex]:
[tex]\sin 99.40° \approx 0.9848[/tex]
[tex]\sin 45.60° \approx 0.7150[/tex]Substitute into the equation:
[tex]\frac{c}{0.9848} = \frac{38.5}{0.7150}[/tex][tex]c \approx 53.02[/tex]
Now we have all the elements of triangle ABC:
- Angle A [tex]\approx 45.60°[/tex]
- Angle B [tex]= 35° 00'[/tex]
- Angle C [tex]\approx 99.40°[/tex]
- Side a [tex]= 38.5[/tex]
- Side b [tex]= 30.9[/tex]
- Side c [tex]\approx 53.02[/tex]
This solution completes the triangle ABC using the provided information.
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