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Answer :
The real solutions to the quadratic equation 4c^(2)+17c+12=0 are (-17 + √(97))/(8) and (-17 - √(97))/(8).
To find the real solutions of the quadratic equation 4c^(2) + 17c + 12 = 0, we can use the quadratic formula:
c = (-b ± √(b^2 - 4ac))/2a
Substituting the values a = 4, b = 17, and c = 12 into the formula, we get:
c = (-17 ± √(17^2 - 4(4)(12)))/(2(4))
Simplifying the expression further, we have:
c = (-17 ± √(289 - 192))/(8)
c = (-17 ± √(97))/(8)
Therefore, the solutions to the equation are:
c = (-17 + √(97))/(8) and c = (-17 - √(97))/(8).
Learn more about Quadratic equations here:
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