Answer :

Answer:

B. 62

Step-by-step explanation:

[tex]\arccos(\frac{8^2+17^2-15^2}{2(8)(17)})=\arccos(\frac{64+289-225}{16\times17})=\arccos(\frac{128}{272})[/tex]

[tex]\arccos(\frac{8}{17})[/tex]

∠A = 1.08084 rad = 61.928°

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Rewritten by : Barada

Answer:

The option B is true.

Step-by-step explanation: