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Answer :
To solve the problem, we'll find the mean, median, and midrange of the given scores: 68, 62, 60, 64, 70, 66, and 72. Let's break this down step by step:
1. Mean:
- First, add up all the scores: [tex]\(68 + 62 + 60 + 64 + 70 + 66 + 72 = 462\)[/tex].
- Since there are 7 scores, divide the total by 7:
[tex]\[
\text{Mean} = \frac{462}{7} = 66
\][/tex]
2. Median:
- To find the median, first arrange the scores in ascending order: 60, 62, 64, 66, 68, 70, 72.
- Since there are 7 scores (an odd number), the median is the middle number, which is the 4th number in this ordered list: 66.
3. Midrange:
- The midrange is calculated as the average of the smallest and largest numbers in the set.
- The smallest score is 60, and the largest score is 72.
- So the midrange is:
[tex]\[
\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66
\][/tex]
After calculating the mean, median, and midrange, we find that each of these values is 66. Therefore, the choice that corresponds to this result is:
- Mean = 66, Median = 66, Midrange = 66
The correct answer is d. Mean = 66, Median = 66, Midrange = 66.
1. Mean:
- First, add up all the scores: [tex]\(68 + 62 + 60 + 64 + 70 + 66 + 72 = 462\)[/tex].
- Since there are 7 scores, divide the total by 7:
[tex]\[
\text{Mean} = \frac{462}{7} = 66
\][/tex]
2. Median:
- To find the median, first arrange the scores in ascending order: 60, 62, 64, 66, 68, 70, 72.
- Since there are 7 scores (an odd number), the median is the middle number, which is the 4th number in this ordered list: 66.
3. Midrange:
- The midrange is calculated as the average of the smallest and largest numbers in the set.
- The smallest score is 60, and the largest score is 72.
- So the midrange is:
[tex]\[
\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66
\][/tex]
After calculating the mean, median, and midrange, we find that each of these values is 66. Therefore, the choice that corresponds to this result is:
- Mean = 66, Median = 66, Midrange = 66
The correct answer is d. Mean = 66, Median = 66, Midrange = 66.
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