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Answer :
Final answer:
The distance travelled by the proton before it momentarily stops can be calculated by using the kinematic equation of motion and the physics concept of force in a uniform electric field.
Explanation:
The problem deals with the subject of physics, specifically involving motion in a uniform electric field. To calculate the distance travelled by the proton before it stops momentarily, we'll make use of the equation of kinematic motion, v^2 = u^2 + 2as. Here, 'u' is the initial velocity, 'v' is the final velocity (which is 0, as the proton stops momentarily), 'a' is the acceleration, and 's' is the distance travelled.
As the proton is projected against a uniform field, it experiences a force that slows it down. The force exerted on it equals the charge of the proton times the electric field (F = qE). For a proton, q (charge) is 1.6×10^-19 Coulombs. The acceleration 'a', therefore, would be the force divided by the mass of the proton, which is 1.67×10^-27 kg.
We can put these values into our kinematic equation to find the distance 's'.
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