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Answer :
Answer:
B) 79.5L
Explanation:
To determine the maximum amount of gas product that can be formed, we need to determine the limiting reagent in the reaction between hydrogen gas (H2) and chlorine gas (Cl2). The stoichiometric ratio between H2 and Cl2 is 1:1, meaning that one mole of H2 reacts with one mole of Cl2.
Given that the volume of hydrogen gas is 159 L and the volume of chlorine gas is 79.5 L, we can use the ideal gas law to calculate the number of moles for each gas:
Number of moles of H2 = volume of H2 / molar volume at STP
= 159 L / 22.4 L/mol
= 7.1 mol
Number of moles of Cl2 = volume of Cl2 / molar volume at STP
= 79.5 L / 22.4 L/mol
= 3.55 mol
Comparing the number of moles of H2 and Cl2, we can see that there is an excess of hydrogen gas. Therefore, chlorine gas is the limiting reagent.
Since the stoichiometric ratio is 1:1, the maximum amount of product that can be formed is equal to the number of moles of the limiting reagent, which is 3.55 mol.
To calculate the volume of the gas product at STP, we can use the ideal gas law:
Volume of gas product = number of moles of gas product * molar volume at STP
= 3.55 mol * 22.4 L/mol
= 79.52 L
Therefore, the maximum amount of gas product that can be formed at STP is approximately 79.5 L.
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