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Answer :
Final answer:
The balanced equation is: 3CuO + 2Al = Al2O3 + 3Cu. To produce 36.3 g of Al2O3, you would need 74.9 g of CuO.
Explanation:
To balance the equation CuO + Al = Al2O3 + Cu, we first make sure that the same number of atoms of each element appears on both sides of the equation. After balancing, we get the equation: 3CuO + 2Al = Al2O3 + 3Cu.
Now, to determine the number of grams of CuO needed to produce 36.3 g of Al2O3, we need to use the stoichiometry of the balanced equation. The molar mass of Al2O3 is approximately 101.96 g/mol, and using the equation, you can see that 2 moles of Al produce 101.96 g of Al2O3. So, to produce 36.3 g, you would need (36.3 g / 101.96 g/mol) * 2 moles of Al.
Next, using the stoichiometry from the balanced equation, 3 moles of CuO produce 2 moles of Al2O3. Therefore, you need to calculate how many grams of CuO are required to provide the moles of Al2O3 needed, which comes to 74.9 g of CuO.
This process ensures that you have the correct stoichiometric ratio to produce 36.3 g of Al2O3.
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