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Answer :
We start with the formula for momentum:
[tex]$$
p = m \cdot v
$$[/tex]
where
[tex]\( p \)[/tex] is the momentum,
[tex]\( m \)[/tex] is the mass, and
[tex]\( v \)[/tex] is the velocity.
To find the mass, we rearrange the formula to solve for [tex]\( m \)[/tex]:
[tex]$$
m = \frac{p}{v}
$$[/tex]
Given that
[tex]\( p = 36 \, \text{kg} \cdot \text{m/s} \)[/tex] and [tex]\( v = 4 \, \text{m/s} \)[/tex], we substitute these values into the equation:
[tex]$$
m = \frac{36 \, \text{kg} \cdot \text{m/s}}{4 \, \text{m/s}} = 9 \, \text{kg}
$$[/tex]
Thus, the mass of the bicycle is [tex]\( \boxed{9 \, \text{kg}} \)[/tex].
[tex]$$
p = m \cdot v
$$[/tex]
where
[tex]\( p \)[/tex] is the momentum,
[tex]\( m \)[/tex] is the mass, and
[tex]\( v \)[/tex] is the velocity.
To find the mass, we rearrange the formula to solve for [tex]\( m \)[/tex]:
[tex]$$
m = \frac{p}{v}
$$[/tex]
Given that
[tex]\( p = 36 \, \text{kg} \cdot \text{m/s} \)[/tex] and [tex]\( v = 4 \, \text{m/s} \)[/tex], we substitute these values into the equation:
[tex]$$
m = \frac{36 \, \text{kg} \cdot \text{m/s}}{4 \, \text{m/s}} = 9 \, \text{kg}
$$[/tex]
Thus, the mass of the bicycle is [tex]\( \boxed{9 \, \text{kg}} \)[/tex].
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