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When a 6 Ω resistor is connected across the terminals of a 3 V battery, how many coulombs pass through the resistor per second?

Answer :

Answer:

Given that - R = 6 ohm


V = 3 volt


n = ?


so by ohms law , V = I X R

I = V \ R = 3 \ 6 = 0.5 A



we know that I = Q / T here t is 1 sec


Q = I X T = 0.5 X 1 = 0.5 C


By the law of quantization ,


Q = n x e


n = Q / e = 0.5 / 1.6 x 10 ^-19


n = 0.3125 x 10^19


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Rewritten by : Barada

Answer:

0.5/1.6×10^-19

Explanation:

formula for current is v

I R

3/6=0.5

charge if found by the product of current and time which is one second

0.5×1 =0.5

deficiency of n=no of charges×charge of electrons

0.5/1.6×10^-19