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A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling at 120 meters per second and decelerates to a velocity of 20 meters per second. What was its acceleration?

A. \(-1.11 \, \text{m/s}^2\) (negative 1.11 meters per second squared)
B. \(-0.3 \, \text{m/s}^2\) (negative 0.3 meters per second squared)
C. \(1.11 \, \text{m/s}^2\) (positive 1.11 meters per second squared)
D. \(80 \, \text{m/s}^2\)

Answer :

Answer:

A. −1.11 m/s2

Explanation:

To calculate the object's acceleration, we can say:

acceleration = (final velocity - initial velocity) / time

The object's initial velocity is 120 m/s, its final velocity is 20 m/s, and the time it takes to travel the 2,500-meter path is 1.5 minutes, or 90 seconds (1.5 x 60 = 90).

Therefore:

acceleration = (20 m/s - 120 m/s) / 90 s = -1.11 m/s^2

Note

The negative sign, means the object is decelerating and not accelerating because the object is slowing down during the trip.

it is decreasing its speed as it travels, so it's slowing down over time. The absolute value of -1.11 is also called deceleration.#SPJ4

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