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Tryptophan is an amino acid abbreviated as HTrp. If 46.25 mL of 0.558 M Sr(OH)2 neutralizes 6.49 g of HTrp, what is the molar mass of the amino acid?

The balanced equation is:
2 HTrp(aq) + Sr(OH)2(aq) → Sr(Trp)2(aq) + 2 H2O(l)

Answer :

To find the molar mass of an amino acid, we can use the volume and concentration of the reactant in a neutralization reaction and the balanced equation to determine the number of moles of the amino acid. Finally, we can calculate the molar mass by dividing the mass of the amino acid by the number of moles.

To find the molar mass of the amino acid, we need to first determine the number of moles of Sr(OH)2 used in the neutralization reaction. This can be done by using the given concentration and volume of Sr(OH)2. Next, we can use the balanced equation to determine the number of moles of HTrp that reacted with the moles of Sr(OH)2. Finally, by dividing the mass of HTrp by the number of moles, we can calculate its molar mass.


Step 1: Calculate the number of moles of Sr(OH)2


Step 2: Use the mole ratio from the balanced equation to determine the number of moles of HTrp

Step 3: Calculate the molar mass of HTrp by dividing the mass by the number of moles

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