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a security guard is tasked with taking people's temperature before they can enter the library. by default he assumes their temperature is at 99.2 degrees or above and they should be banned. he aims a temperature gun at them 7 times and if they are significantly below 99.2 (at the 0.19 significance level) then they are allowed inside. he assumes normality and that the temperature gun has standard deviation of 0.6962 degrees. if the next person actually has a temperature of 99.1 how powerful is this security guards test?

Answer :

The power of the security guard's test is approximately 0.0985, or 9.85%.

To determine the power of the security guard's test, we need to calculate the probability that the test correctly identifies someone with a temperature below 99.2 degrees. First, let's define our hypotheses:

- Null hypothesis (H0): The person's temperature is 99.2 degrees or above.

- Alternative hypothesis (Ha): The person's temperature is below 99.2 degrees.

Next, we need to calculate the critical value for the test. Since the significance level is given as 0.19, the critical value will be obtained from the Z-table.

Using the formula Z = (X - μ) / σ, where X is the observed temperature (99.1), μ is the assumed temperature (99.2), and σ is the standard deviation (0.6962), we can calculate the Z-value.

Z = (99.1 - 99.2) / 0.6962 = -0.1439

Consulting the Z-table, we find that the critical Z-value for a significance level of 0.19 is approximately -1.29.

Now, we can calculate the power of the test. Power is equal to 1 minus the probability of committing a Type II error, which is the probability of failing to reject the null hypothesis when it is false.

To calculate the power, we need to find the area under the alternative hypothesis curve to the right of the critical value (-1.29). This can also be found using the Z-table. The power is the probability that the observed temperature falls within this region.

In this case, since the observed temperature (99.1) is below the assumed temperature (99.2), the power would be the probability that the observed temperature is less than the critical value (-1.29).

By consulting the Z-table, we find that the probability is approximately 0.0985.

Therefore, the power of the security guard's test is approximately 0.0985, or 9.85%.

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