We appreciate your visit to An 80 0kg hockey player collides head on with a 65 0kg hockey player If the more massive player experiences a 3 50 m s². This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The less massive player experiences an acceleration of 4.31 m/s².
In this problem, we are dealing with Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. If the 80.0-kg hockey player (Player 1) undergoes an acceleration of -3.50 m/s², we can find the force exerted on Player 1 using the formula:
F = m * a
Here, m is the mass of Player 1, and a is their acceleration:
F = 80.0 kg * -3.50 m/s² = -280.0 N
According to Newton's Third Law, Player 2 also experiences a force of equal magnitude but in the opposite direction. So, the force exerted on the 65.0-kg hockey player (Player 2) is +280.0 N.
Using Newton's Second Law (F = m * a), we can find the acceleration of Player 2:
280.0 N = 65.0 kg * a
Solving for a, we get:
a = 280.0 N / 65.0 kg = 4.31 m/s²
Therefore, the less massive player experiences an acceleration of 4.31 m/s².
Thanks for taking the time to read An 80 0kg hockey player collides head on with a 65 0kg hockey player If the more massive player experiences a 3 50 m s². We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
