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Solve the missing elements for each problem. Use 3.14 for \(\pi\).

1) s r t q
- Radius: ______________
- Diameter: ______________
- Diameter given: 4 inches
- Circumference: ______________
- Area: ______________

2) c b d a
- Radius: ______________
- Diameter: ______________
- Diameter given: 10 ft
- Circumference: ______________
- Area: ______________

3) r q s p
- Radius: ______________
- Radius given: 18 yards
- Diameter: ______________
- Circumference: ______________
- Area: ______________

4) p o q n
- Radius: ______________
- Diameter: ______________
- Diameter given: 16 cm
- Circumference: ______________
- Area: ______________

5) e d f c
- Radius: ______________
- Radius given: 19 mm
- Diameter: ______________
- Circumference: ______________
- Area: ______________

6) d c e b
- Radius: ______________
- Radius given: 12 inches
- Diameter: ______________
- Circumference: ______________
- Area: ______________

7) j h k g
- Radius: ______________
- Diameter: ______________
- Diameter given: 28 ft
- Circumference: ______________
- Area: ______________

8) n m o l
- Radius: ______________
- Radius given: 6 yards
- Diameter: ______________
- Circumference: ______________
- Area: ______________

9) h g j f
- Radius: ______________
- Diameter: ______________
- Diameter given: 18 cm
- Circumference: ______________
- Area: ______________

Answer :

Final answer:

To solve for missing elements in circle geometry problems, use the formulas Circumference (C) = 2πr and Area (A) = πr², with π approximated as 3.14. Here, r represents the circle's radius. Apply these formulas to fill in the missing values for radius, diameter, circumference, and area.

Explanation:

Solving for Missing Elements in Circle Geometry

To solve the missing elements for each problem, we apply the formulas for the circumference and area of a circle using 3.14 for π (pi). The formulas to remember are: Circumference (C) = 2πr and Area (A) = πr², where 'r' represents the radius of the circle, and the diameter (D) is simply twice the radius (D = 2r).

Let's solve one example to illustrate:

The student can follow this example to solve for the missing elements in other given problems, using the correct values for the radius as provided or derived from the given diameters.

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Rewritten by : Barada

we know that
diameter=radius*2
radius=diameter/2
area of circle=pi*r²
length of circumference=2*pi*r
so

Part 1) 4 inches circumference
4=2*pi*r--------> r=4/(2*pi)-----> r=2/pi-----> r=0.64 in
diameter=2*0.64-----> 1.28 in
area=pi*0.64²------> 1.29 in²

the answers Part 1) are
a) radius=0.64 in
b) diameter=1.28 in
c) area=1.29 in²

Part 2) 10 ft circumference
10=2*pi*r-----> r=10/(2*pi)----> r=5/pi-----> 1.59 ft
diameter=2*1.59------> 3.18 ft
area=pi*1.59
²-----> 7.94 ft²

the answers Part 2) are
a) radius=1.59 ft
b) diameter=3.18 ft
c) area=7.94 ft²

Part 3) 18 yards diameter
radius=18/2-----> 9 yd
circumference=2*pi*9-----> 56.52 yd
area=pi*9
²-----> 254.34 yd²

the answers part 3) are
radius=9 yd
circumference=56.52 yd
area=254.34 yd²

Part 4) 16 cm circumference
16=2*pi*r-----> r=16/(2*pi)----> r=8/pi-----> 2.55 cm
diameter=2*2.55------> 5.10 cm
area=pi*2.55²-----> 20.42 cm²

the answers Part 4) are
a) radius=2.55 cm
b) diameter=5.10 cm
c) area=20.42 cm²

Part 5) 19 mm diameter
radius=19/2-----> 9.5 mm
circumference=2*pi*9.5-----> 59.66 mm
area=pi*9.5²-----> 283.39 mm²

the answers part 5) are
radius=9.5 mm
circumference=59.66 mm
area=283.39 mm²

Part 6) 12 inches diameter
radius=12/2-----> 6 in
circumference=2*pi*6-----> 37.68 in
area=pi*6²-----> 113.04 in²

the answers part 6) are
radius=6 in
circumference=37.68 in
area=113.04 in²

Part 7) 28 ft circumference
28=2*pi*r-----> r=28/(2*pi)----> r=14/pi-----> 4.46 ft
diameter=2*4.46------> 8.92 ft
area=pi*4.46²-----> 62.46 ft²

the answers Part 7) are
a) radius=4.46 ft
b) diameter=8.92 ft
c) area=62.46 ft²

Part 8)
6 yards diameter
radius=6/2-----> 3 yd
circumference=2*pi*3-----> 18.84 yd
area=pi*3²-----> 28.26 yd²

the answers part 8) are
radius=3 yd
circumference=18.84 yd
area=28.26 yd²

Part 9) 18 cm circumference
18=2*pi*r-----> r=18/(2*pi)----> r=9/pi-----> 2.87 cm
diameter=2*2.87------> 5.74 cm
area=pi*2.87²-----> 25.86 cm²

the answers Part 9) are
a) radius=2.87 cm
b) diameter=5.74 cm
c) area=25.86 cm²