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Three beakers contain different volumes of water: 8.1 cm³, 0.64 L, and 2.7 dL. If all three volumes were mixed together in a larger container, what would the final volume in mL be?

Answer :

The final volume, when all three beakers are mixed together, would be 918.1 mL.

To solve this problem, we need to convert the given volumes to a consistent unit, such as milliliters (mL), and then add them together.

Given:

Volume of water in the first beaker = 8.1 cm³

Volume of water in the second beaker = 0.64 L

Volume of water in the third beaker = 2.7 dL

1 liter (L) = 1000 milliliters (mL)

1 deciliter (dL) = 100 milliliters (mL)

1 centimeter cubed (cm³) = 1 milliliter (mL)

Converting the volumes to milliliters (mL):

Volume of water in the first beaker = 8.1 cm³ = 8.1 mL

Volume of water in the second beaker = 0.64 L = 0.64 * 1000 mL = 640 mL

Volume of water in the third beaker = 2.7 dL = 2.7 * 100 mL = 270 mL

Now, we can add the volumes together to find the final volume:

Final volume = 8.1 mL + 640 mL + 270 mL = 918.1 mL

Therefore, the final volume, when all three beakers are mixed together, would be 918.1 mL.

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