High School

We appreciate your visit to What is the product of the polynomials below tex left 5x 2 x 3 right 2x 6 tex A tex 10x 3 28x 2 12x. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

What is the product of the polynomials below?

[tex]\left(5x^2 - x - 3\right)(2x + 6)[/tex]

A. [tex]10x^3 + 28x^2 - 12x - 18[/tex]
B. [tex]10x^3 + 28x^2 + 12x + 18[/tex]
C. [tex]10x^3 + 28x^2 + 12x + 3[/tex]
D. [tex]10x^3 + 28x^2 - 12x - 3[/tex]

Answer :

To find the product of the polynomials [tex]\((5x^2 - x - 3)\)[/tex] and [tex]\((2x + 6)\)[/tex], we'll multiply each term in the first polynomial by each term in the second polynomial. Let's go through the steps:

1. Distribute [tex]\(5x^2\)[/tex]:
- Multiply [tex]\(5x^2\)[/tex] by each term in [tex]\((2x + 6)\)[/tex]:
- [tex]\(5x^2 \times 2x = 10x^3\)[/tex]
- [tex]\(5x^2 \times 6 = 30x^2\)[/tex]

2. Distribute [tex]\(-x\)[/tex]:
- Multiply [tex]\(-x\)[/tex] by each term in [tex]\((2x + 6)\)[/tex]:
- [tex]\(-x \times 2x = -2x^2\)[/tex]
- [tex]\(-x \times 6 = -6x\)[/tex]

3. Distribute [tex]\(-3\)[/tex]:
- Multiply [tex]\(-3\)[/tex] by each term in [tex]\((2x + 6)\)[/tex]:
- [tex]\(-3 \times 2x = -6x\)[/tex]
- [tex]\(-3 \times 6 = -18\)[/tex]

4. Combine all the results:
- Combine all these terms together:
[tex]\[
10x^3 + 30x^2 - 2x^2 - 6x - 6x - 18
\][/tex]

5. Simplify by combining like terms:
- Combine the [tex]\(x^2\)[/tex] terms: [tex]\(30x^2 - 2x^2 = 28x^2\)[/tex]
- Combine the [tex]\(x\)[/tex] terms: [tex]\(-6x - 6x = -12x\)[/tex]

Putting it all together, the product of the polynomials is:
[tex]\[
10x^3 + 28x^2 - 12x - 18
\][/tex]

Thus, the correct answer is option A: [tex]\(10x^3 + 28x^2 - 12x - 18\)[/tex].

Thanks for taking the time to read What is the product of the polynomials below tex left 5x 2 x 3 right 2x 6 tex A tex 10x 3 28x 2 12x. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada