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During each cycle of operation, a refrigerator absorbs 55 cal from the freezer compartment and expels 85 cal to the room. If one cycle occurs every 10 seconds, how many minutes will it take to freeze 500 g of water, initially at 0°C? (L_v = 80 cal/g)

Answer :

The refrigerator will absorb 400 cal of energy from the freezer compartment and expel 320 cal of energy into the room per cycle, and it will take about 16 minutes to freeze 500 g of water.

The amount of energy absorbed by the refrigerator from the freezer compartment and expelled to the room during each cycle of operation can be calculated using the formula:

Lv × m, where Lv is the latent heat of vaporization of water (80 cal/g) and m is the mass of water (500 g).

Thus, the refrigerator will absorb 400 cal of energy

(Lv × m = 80 cal/g × 500 g = 400 cal) from the freezer compartment and expel 320 cal of energy (80 cal/g × 400 g = 320 cal) into the room per cycle.

Since one cycle occurs every 10 seconds, it will take about 16 minutes (960 seconds) to freeze 500 g of water, initially at 0°C.

Complete Question:

During each cycle of operation, how much energy does a refrigerator absorb from the freezer compartment and expel to the room. If one cycle occurs every 10 seconds, how many minutes will it take to freeze 500 g of water, initially at 0°C? (Lv = 80 cal/g)?

To learn more about vaporization visit:

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