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Answer :
The frequency of the 10 inch violin string will be 630 cycles per second or Hertz if the violin string 14 inches long vibrates at a frequency of 450 cycles per second.
As per the question statement, A violin string 14 inches long vibrates at a frequency of 450 cycles per second and we are supposed to find out the frequency of a 10-inch violin string.
We should be knowing that the length of a violin string varies inversely as the frequency of its vibrations.
f = m/l, where "f" is the frequency and "l" is the length and "m" is the constant number
450 = m / 14
m = 6300
Therefore New frequency = 6300 / 10 = 630 cycles per second
- Frequency: The number of oscillations or cycles per second or per unit time and it's SI unit is Hertz or cycles per second.
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