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Answer :
Question is incomplete. Answering in a general way;
The side CA has a length of [tex]\sqrt{c^{2}-b^{2} }[/tex] and Angle C is of 28 degrees.
Given,
Right angled triangle ABC
Length of side AB = b
Length of side BC = c
Angle B = 62°
Angle A = 90°
We have to find the length of side CA and Angle C;
Here,
According to Pythagorean theorem,
Hypotenuse = [tex]\sqrt{base^{2}+altitude^{2} }[/tex]
Here,
Altitude = [tex]\sqrt{Hypotenuse^{2} -Base^{2} }[/tex]
CA = [tex]\sqrt{c^{2} -b^{2} }[/tex]
Now,
Sum of interior angles of a triangle is 180°
Then,
∠A + ∠B + ∠C = 180°
So,
90° + 62° + ∠C = 180°
∠C = 180° - 152°
∠C = 28°
That is,
The length of side CA is [tex]\sqrt{c^{2}-b^{2} }[/tex] and Angle C is 28°
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