We appreciate your visit to A wave travels down a string with a velocity of 512 m s If the string has a length of 6 84 meters what is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The second harmonic frequency of a string can be calculated using the formula f_n = n(v/2L). Given the velocity of 512 m/s and length of 6.84 meters, the second harmonic frequency is found to be 74.9 Hz, matching option b.
Explanation:
To find the second harmonic frequency of a string, we first need to understand that the frequency of the nth harmonic can be calculated using the formula f_n = n(v/2L), where v is the velocity of the wave, L is the length of the string, and n represents the harmonic number. In this case, the second harmonic (n=2) is in question.
Given that the velocity (v) of the wave is 512 m/s, and the length (L) of the string is 6.84 meters, we can substitute these values into the formula:
f_2 = 2(512 m/s / 2*6.84 m) = 74.9 Hz
Therefore, the second harmonic frequency of this string is 74.9 Hz, which corresponds to option b.
Thanks for taking the time to read A wave travels down a string with a velocity of 512 m s If the string has a length of 6 84 meters what is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
